2008 Spring Qualifying Exam in Complex Analysis
Problem 1.
Find explicitly a conformal mapping of
onto the unit disk.
Proof.
The map
sends the exterior first-quadrant domain onto the quarter unit disk
Then
maps the upper half unit disk onto the first quadrant. Squaring maps the first quadrant onto the upper half-plane, and
maps the upper half-plane onto the unit disk.
Thus one explicit conformal map is
Problem 2.
Let
for all
for some constant
Proof.
At every zero of
has removable singularities at the zeros of
Away from the zeros of
By removability, this bound holds everywhere. Therefore
Problem 3.
Show that there is a holomorphic function on
whose derivative is
Is there a holomorphic function on
Proof.
On the exterior domain
For
we have
Thus there is no
Therefore
For
we have
Hence
So
Problem 4.
Let
Proof.
No.
By the Schwarz-Pick derivative estimate,
Taking
But
Thus no such holomorphic map exists.
Problem 5.
Evaluate
Proof.
Although the denominator vanishes at
Consider
and close the contour in the upper half-plane, indenting above the pole at
The residue at
The indented pole at
Thus the principal value of the complex exponential integral is
Since
the first term is real. Therefore the imaginary part is
Hence
Problem 6.
Prove that
converges uniformly on compact sets to an entire function.
Proof.
Write each factor as
where
On a compact set
and
Both
converge. Hence
converges.
Therefore the infinite product
Problem 7.
Let
Prove that
Proof.
Write
Then
and orthogonality gives
Also
For
By Cauchy-Schwarz,
The second sum is finite for
By Montel's theorem,
Problem 8.
Let
Find all such functions
Proof.
Let
and set
Then
for
By the Schwarz reflection principle,
in the reflected lower half-neighborhood. The extended function vanishes on the interval, which is now a set with accumulation points inside the extended domain. By the identity theorem,
Thus
Problem 9.
Show that there is no holomorphic function
satisfying
Proof.
The inequality implies
takes values in the disk
Fix
around
This is an odd integer.
But
This contradiction proves that no such holomorphic function exists.
